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7x^2+9x-46=0
a = 7; b = 9; c = -46;
Δ = b2-4ac
Δ = 92-4·7·(-46)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-37}{2*7}=\frac{-46}{14} =-3+2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+37}{2*7}=\frac{28}{14} =2 $
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